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Reusing an image variable does NOT clear the old data out of memory! And to continue what Docey said, if php did not destroy all resources when the script stopped it would be a huge memory leak and everyone would be crying out for it to be fixed right away.

I have been using this function during a script that was breaking an image made of many little icons into the little parts, which could mean 400 images in the one script, which was using a lot of memory so I needed to destroy them.

Caution should be observed with imagedestroy(); copying your reference variable over to another variable will cause imagedestroy to destroy both at once.

Eg.: $a = imagecreate(...);$b = $a;imagedestroy($a); While you'd think $b still contains your image, it doesn't. When working with a lot of high-resolution images, it's IMPERATIVE that you use the imagedestroy() function.

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Reusing an image variable does NOT clear the old data out of memory! And to continue what Docey said, if php did not destroy all resources when the script stopped it would be a huge memory leak and everyone would be crying out for it to be fixed right away.

I have been using this function during a script that was breaking an image made of many little icons into the little parts, which could mean 400 images in the one script, which was using a lot of memory so I needed to destroy them.

Caution should be observed with imagedestroy(); copying your reference variable over to another variable will cause imagedestroy to destroy both at once.

Eg.: $a = imagecreate(...);$b = $a;imagedestroy($a); While you'd think $b still contains your image, it doesn't. When working with a lot of high-resolution images, it's IMPERATIVE that you use the imagedestroy() function.

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